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Question
(2xy + 3y2) (3y2 − 2)
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Solution
To multiply, we will use distributive law as follows:
\[\left( 2xy + 3 y^2 \right)\left( 3 y^2 - 2 \right)\]
\[ = 2xy\left( 3 y^2 - 2 \right) + 3 y^2 \left( 3 y^2 - 2 \right)\]
\[ = 6x y^3 - 4xy + 9 y^4 - 6 y^2 \]
\[ = 9 y^4 + 6x y^3 - 6 y^2 - 4xy\]
Thus, the answer is \[9 y^4 + 6x y^3 - 6 y^2 - 4xy\].
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