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Question
\[\ce{^290_80X ->[\alpha] Y ->[e+] Z ->[\beta-] P ->[e-] Q}\]
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are:
Options
288, 82
286, 81
280, 81
286, 80
MCQ
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Solution
286, 81
Explanation:
\[\ce{^290_80X ->[\alpha] ^286_80Y ->[e+] ^286_79Z ->[\beta-] ^286_80P ->[e-] ^286_81Q}\]
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