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Question
28x2 – 7y2 is equal to ______.
Options
7(x + 4y) (x – 4y)
7(4x + y) (4x – y)
7(2x + y) (2x – y)
7(x + y) (x – y)
MCQ
Fill in the Blanks
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Solution
28x2 – 7y2 is equal to 7(2x + y) (2x – y).
Explanation:
Let’s factorise the given expression:
28x2 – 7y2
Step 1: Factor out the common factor of 7:
28x2 – 7y2 = 7(4x2 – y2)
Step 2: Recognise that 4x2 – y2 is a difference of squares:
4x2 – y2 = (2x + y) (2x – y)
Step 3: Substitute back into the expression:
7(4x2 – y2) = 7(2x + y) (2x – y)
Thus, the factorisation is 7(2x + y) (2x – y)
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