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Question
20 tickets, on which numbers 1 to 20 are written, are mixed thoroughly and then a ticket is drawn at random out of them. Find the probability that the number on the drawn ticket is a multiple of 3 or 7 ?
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Solution
Total number of outcomes = 20
Possible outcomes = 3, 6, 7, 9, 12, 14, 15 and 18
∴ Number of favourable outcomes = 8
Probability =\[\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}\]
\[\therefore \text{Probability that the number on the drawn ticket is a multiple of 3 or 7 =} \frac{8}{20} = \frac{2}{5}\]
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