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Question
`(2 cos 67^circ)/(sin 23^circ) - (tan 40^circ)/(cot 50^circ) - cos 0^circ` = ______.
Fill in the Blanks
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Solution
`(2 cos 67^circ)/(sin 23^circ) - (tan 40^circ)/(cot 50^circ) - cos 0^circ` = 0.
Explanation:
`(2 cos 67^circ)/(sin 23^circ) - (tan 40^circ)/(cot 50^circ) - cos 0^circ`
= `(2 cos(90^circ - 23^circ))/(sin 23^circ) - (tan(90^circ - 50^circ))/(cot 50^circ) - cos 0^circ`
= `(2 sin 23^circ)/(sin 23^circ) - (cot 50^circ)/(cot 50^circ) - cos 0^circ`
= 2 – 1 – 1 ...[∵ cos 0° = 1]
= 0
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