Question

`(2  cos 67^circ)/(sin 23^circ) - (tan 40^circ)/(cot 50^circ) - cos 0^circ` = ______.

Answer 1

`(2  cos 67^circ)/(sin 23^circ) - (tan 40^circ)/(cot 50^circ) - cos 0^circ` = 0.

Explanation:

`(2  cos 67^circ)/(sin 23^circ) - (tan 40^circ)/(cot 50^circ) - cos 0^circ`

= `(2 cos(90^circ - 23^circ))/(sin 23^circ) - (tan(90^circ - 50^circ))/(cot 50^circ) - cos 0^circ`

= `(2  sin 23^circ)/(sin 23^circ) - (cot 50^circ)/(cot 50^circ) - cos 0^circ`

= 2 – 1 – 1   ...[∵ cos 0° = 1]

= 0