Advertisements
Advertisements
Question
`(125 xx x^-3)/(5^-3 xx 25 xx x^-6)`
Advertisements
Solution
Using laws of exponents,
am + an = (a)n – m and `a^-m = 1/a^m` ...[∵ a is non-zero integer]
∴ `(125 xx x^-3)/(5^-3 xx 25 xx x^-6) = (5)^3 xx 5^3 xx 5^-2 xx x^-3 xx x^6` ....`[(∵ 125 = 5 xx 5 xx 5),("and" 25 = 5 xx 5)]`
= 54 × x3
= 5 × 5 × 5 × 5 × x3 ...[∵ am × an = am + n]
= 625 x3
APPEARS IN
RELATED QUESTIONS
If x be any integer different from zero and m, n be any integers, then (xm)n is equal to ______.
For a non-zero integer x, (x4)–3 is equal to ______.
The value of 5–2 is equal to 25.
Simplify:
`(((-2)/3)^-2)^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Find the value of x so that (2–1 + 4–1 + 6–1 + 8–1)x = 1
By what number should (–15)–1 be divided so that quotient may be equal to (–15)–1?
By what number should `((-3)/2)^-3` be divided so that the quotient may be `(4/27)^-2`?
A new born bear weighs 4 kg. How many kilograms might a five year old bear weigh if its weight increases by the power of 2 in 5 years?
Find a single repeater machine that will do the same work as hook-up.

Supply the missing information for diagram.

