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Question
`int_1^2 1/(2x + 3) dx` = ______
Fill in the Blanks
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Solution
`int_1^2 1/(2x + 3) dx` = `bbunderline(1/2 log(7/5))`
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Is there an error in this question or solution?
`int_1^2 1/(2x + 3) dx` = ______
`int_1^2 1/(2x + 3) dx` = `bbunderline(1/2 log(7/5))`