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Question
(1 + tan2 A) × cos2 A − 1 is ______.
Options
1
−2
0
2
MCQ
Fill in the Blanks
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Solution
(1 + tan2 A) × cos2 A − 1 is 0.
Explanation:
Solving,
\[\Rightarrow (1 + \tan^2 A) \times \cos^2 A - 1\]
\[\Rightarrow \left(1 + \frac{\sin^2 A}{\cos^2 A}\right) \times \cos^2 A - 1\]
\[\Rightarrow \left(\frac{\cos^2 A + \sin^2 A}{\cos^2 A}\right) \times \cos^2 A - 1\]
\[\Rightarrow \frac{1}{\cos^2 A} \times \cos^2 A - 1\]
\[\Rightarrow 1 - 1\]
\[\Rightarrow 0.\]
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