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∫ 1 √ ( 2 − X ) 2 + 1 D X - Mathematics

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Question

\[\int\frac{1}{\sqrt{\left( 2 - x \right)^2 + 1}} dx\]
Sum
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Solution

\[\int\frac{dx}{\sqrt{\left( 2 - x \right)^2 + 1}}\]
\[\text{ let 2 }- x = t\]
\[ \Rightarrow - dx = dt\]
\[ \Rightarrow dx = - dt\]
\[Now, \int\frac{dx}{\sqrt{\left( 2 - x \right)^2 + 1}}\]
\[ = - \int\frac{dt}{\sqrt{t^2 + 1}}\]
\[ = - \text{ log }\left| t + \sqrt{t^2 + 1} \right| + C\]
\[ = - \text{ log }\left| \left( 2 - x \right) + \sqrt{\left( 2 - x \right)^2 + 1} \right| + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.14 [Page 83]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.14 | Q 8 | Page 83

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