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Question
`|(0, xyz, x - z),(y - x, 0, y z),(z - x, z - y, 0)|` = ______.
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Solution
`|(0, xyz, x - z),(y - x, 0, y z),(z - x, z - y, 0)|` = (y – z)(z – x)(y – x + xyz).
Explanation:
Let Δ = `|(0, xyz, x - z),(y - x, 0, y z),(z - x, z - y, 0)|`
C1 → C1 – C3
= `|(z - x, xyz, x - z),(z - x, 0, y - z),(z - x, z - y, 0)|`
Taking (z – x) common from C1
= `(z - x) |(1, xyz, x - z),(1, 0, y - z),(1, z - y, 0)|`
R1 → R1 – R2, R2 → R2 – R3
= `(z - x) |(0, xyz,y),(0, y - x, y - z),(1, z - y, 0)|`
Taking (y – z) common from R2
= `(z - x)(y - z) |(0, xyz, x - y),(0, 1, 1),(1, z - y, 0)|`
Expanding along C1
= `(z - x)(y - z) [1|(xyz, x - y),(1, 1)|]`
= (z – x)(y – z)(xyz – x + y)
= (y – z)(z – x)(y – x + xyz)
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