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0.3605 g of a metal is deposited on the electrode by passing 1.2 amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal? - Chemistry (Theory)

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Question

0.3605 g of a metal is deposited on the electrode by passing 1.2 amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal?

Numerical
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Solution

Weight ‘w’ of the metal = 0.3605 g

Current = 1.2 amp.

Time = 15 min = 15 × 60 sec.

The atomic weight of metal = 96

According to Faraday’s first law of electrolysis,

Electrochemical equivalent, (Z) = `w/(I xx t)`

= `0.3605/(1.2 xx 15 xx 60)`

= 3.34 × 10−4 g c−1

Valency = `"Atomic wt."/"Equivalent wt."`

= `96/(3.34 xx 10^-4 xx 96500)`

= 2.98 (∵ Equivalent wt. = Z × F)

= 3

The valency of the metal is 3.

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States of Matter - Relation Between Radius, Edge Length and Nearest Neighbour Distance of Atoms in a Unit Cell
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