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0.3605 g of a metal is deposited on the electrode by passing 1.2 amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal? - Chemistry (Theory)

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Question

0.3605 g of a metal is deposited on the electrode by passing 1.2 amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal?

Numerical
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Solution

Weight ‘w’ of the metal = 0.3605 g

Current = 1.2 amp.

Time = 15 min = 15 × 60 sec.

The atomic weight of metal = 96

According to Faraday’s first law of electrolysis,

Electrochemical equivalent, (Z) = `w/(I xx t)`

= `0.3605/(1.2 xx 15 xx 60)`

= 3.34 × 10−4 g c−1

Valency = `"Atomic wt."/"Equivalent wt."`

= `96/(3.34 xx 10^-4 xx 96500)`

= 2.98 (∵ Equivalent wt. = Z × F)

= 3

The valency of the metal is 3.

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Chapter 3: Electrochemistry - QUESTIONS FROM ISC EXAMINATION PAPERS [Page 214]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 3 Electrochemistry
QUESTIONS FROM ISC EXAMINATION PAPERS | Q 22. | Page 214
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