Question

0.05 M NaOH solution offered resistance of 31.6 ohms in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm⁻¹, calculate the molar conductivity of the NaOH solution.

Answer 1

Given: Molarity of NaOH solution = 0.05 M

Resistance = 31.6 ohm

Cell constant = 0.367 cm⁻¹

Now,

Molar conductivity = `"Specific conductivity × 1000"/"Molarity"`

= `"cell constant"/"Resistance" xx 1000/"Molarity"`

= `(0.367 xx 1000)/(31.6 xx 0.05)`

= 232.3 ohm⁻¹ cm² mol⁻¹