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Question
`int_0^2 1/sqrt(4 - x^2)dx` = ______
Options
`pi/4`
`pi/3`
`pi/2`
π
MCQ
Fill in the Blanks
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Solution
`int_0^2 1/sqrt(4 - x^2)dx` = `underline(pi/2)`
Explanation:
`int_0^2 1/sqrt(4 - x^2)dx = int_0^2 1/sqrt((2)^2 - x^2)dx`
= `[sin^-1(x/2)]_0^2`
= `sin^-1(1) - sin^-1(0)`
= `pi/2`
shaalaa.com
Some Special Integrals
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