Question

`int_0^2 1/sqrt(4 - x^2)dx` = ______ 

पर्याय

• `pi/4`

• `pi/3`

• `pi/2`

• π

Answer 1

`int_0^2 1/sqrt(4 - x^2)dx` = `underline(pi/2)`

Explanation:

`int_0^2 1/sqrt(4 - x^2)dx = int_0^2 1/sqrt((2)^2 - x^2)dx`

= `[sin^-1(x/2)]_0^2`

= `sin^-1(1) - sin^-1(0)`

= `pi/2`