(English Medium) ICSE Class 10 - CISCE Question Bank Solutions

Express the following in terms of angles between 0° and 45°:

cosec68° + cot72°

Express the following in terms of angles between 0° and 45°:

cos74° + sec67°

For triangle ABC, show that: `sin  (A + B)/2 = cos  C/2`

For triangle ABC, show that : `tan  (B + C)/2 = cot  A/2`

Evaluate:

`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`

Evaluate:

3cos80° cosec10° + 2 sin59° sec31°

Evaluate:

`sin80^circ/(cos10^circ) + sin59^circ  sec31^circ`

Evaluate:

tan(55° - A) - cot(35° + A)

Evaluate:

cosec (65° + A) – sec (25° – A)

Evaluate:

`2 tan57^circ/(cot33^circ) - cot70^circ/(tan20^circ) - sqrt(2)  cos45^circ`

Evaluate:

`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`

Evaluate:

`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`

Evaluate:

14 sin 30° + 6 cos 60° – 5 tan 45°

A triangle ABC is right angles at B; find the value of`(secA.cosecC - tanA.cotC)/sinB`

Find the value of x, if sin x = sin 60° cos 30° – cos 60° sin 30°

Find the value of x, if sin x = sin 60° cos 30° + cos 60° sin 30°

Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°

Find the value of x, if tan x = `(tan60^circ - tan30^circ)/(1 + tan60^circ tan30^circ)`

Find the value of x, if sin 2x = 2 sin 45° cos 45°

Find the value of x, if sin 3x = 2 sin 30° cos 30°