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प्रश्न
Prove that:
sin (28° + A) = cos (62° – A)
बेरीज
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उत्तर
sin (28° + A) = sin [90° – 62° – A] = cos (62° – A)
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पाठ 21: Trigonometrical Identities - Exercise 21 (E) [पृष्ठ ३३२]
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