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ABC is an isosceles triangle in which AB = AC. BE and CF are its two medians. Show that BE = CF.
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In the given figure, ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x is
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D, E, F are the mid-point of the sides BC, CA and AB respectively of ΔABC. Then ΔDEF is congruent to triangle
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If ABCD is a rhombus with ∠ABC = 56°, find the measure of ∠ACD.
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The perimeter of a parallelogram is 22 cm. If the longer side measures 6.5 cm, what is the measure of shorter side?
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If measures opposite angles of a parallelogram are (60 − x)° and (3x − 4)°, then find the measures of angles of the parallelogram.
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In the given figure, ABCD and AEFG are two parallelograms. If ∠C = 58°, find ∠F.
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Complete the following statement by means of one of those given in brackets against each:
If one angle of a parallelogram is a right angle, then it is necessarily a .................
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Complete the following statement by means of one of those given in brackets against each:
Consecutive angles of a parallelogram are ...................
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PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
∠P =85°, ∠Q = 85°, ∠R = 95°
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PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
PQ = 7 cm, QR = 7 cm, RS = 8 cm, SP = 8 cm
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PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
OP = 6.5 cm, OQ = 6.5 cm, OR = 5.2 cm, OS = 5.2 cm
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The bisectors of any two adjacent angles of a parallelogram intersect at
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The bisectors of the angle of a parallelogram enclose a
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The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a
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The figure formed by joining the mid-points of the adjacent sides of a rectangle is a
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If one angle of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is
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In a parallelogram ABCD, if ∠DAB = 75° and ∠DBC = 60°, then ∠BDC =
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ABCD is a parallelogram and E and F are the centroids of triangles ABD and BCDrespectively, then EF =
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ABCD is a parallelogram, M is the mid-point of BD and BM bisects ∠B. Then ∠AMB =
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