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प्रश्न
Plot the following points and write the name of the figure obtained by joining them in order:
P(– 3, 2), Q(– 7, – 3), R(6, – 3), S(2, 2)
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उत्तर
Let X’ OX and Y’ OY be the coordinate axes and mark point on it. Here, point P(– 3, 2) lies in II quadrant, Q(– 7, – 3) lies in III quadrant, R(6, – 3) lies in IV quadrant and S(2, 2) lies in I quadrant. Plotting the points on the graph paper, the figure obtained is trapezium PQRS.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(7, 0)
Plot the following points on the one and the same co-ordinate system.
A(1, 3), B(-3, -1), C(1, -4), D(-2, 3), E(0, -8), F(1, 0)
If P(−1, 1), Q(3, −4), R(1, −1), S(−2, −3) and T(−4, 4) are plotted on a graph paper, then the points in the fourth quadrant are __________
Find the quadrants without plotting the point on a graph sheet.
(5, 7)
Plot the following point in a graph sheet.
F(2, 0)
Find the quadrants without plotting the point on a graph sheet
(4, −3)
In the following figure, coordinates of P are ______.
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
Points A(5, 3), B(– 2, 3) and D(5, – 4) are three vertices of a square ABCD. Plot these points on a graph paper and hence find the coordinates of the vertex C.
From the figure, answer the following:
Write the points whose abscissa is – 5.
