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प्रश्न
Plot the following points and write the name of the figure obtained by joining them in order:
P(– 3, 2), Q(– 7, – 3), R(6, – 3), S(2, 2)
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उत्तर
Let X’ OX and Y’ OY be the coordinate axes and mark point on it. Here, point P(– 3, 2) lies in II quadrant, Q(– 7, – 3) lies in III quadrant, R(6, – 3) lies in IV quadrant and S(2, 2) lies in I quadrant. Plotting the points on the graph paper, the figure obtained is trapezium PQRS.

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संबंधित प्रश्न
Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.
| x | -2 | -1 | 0 | 1 | 3 |
| y | 8 | 7 | -1.25 | 3 | -1 |
Plot the following point on the graph paper:
(7, −4)
Write the equation of the line parallel to the Y-axis at a distance of 7 units from it to its left.
Plot the following points on the one and the same co-ordinate system.
A(1, 3), B(-3, -1), C(1, -4), D(-2, 3), E(0, -8), F(1, 0)
Write down the abscissa and ordinate of the following.
S
Find the quadrants without plotting the point on a graph sheet.
(2, 0)
Plot the following point in a graph sheet.
E(0, −5)
If P(5, 1), Q(8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the point(s) on the x-axis are ______.
Plot the following points and check whether they are collinear or not:
(1, 3), (– 1, – 1), (– 2, – 3)
Taking 0.5 cm as 1 unit, plot the following points on the graph paper:
A(1, 3), B(– 3, – 1), C(1, – 4), D(– 2, 3), E(0, – 8), F(1, 0)
