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प्रश्न
Plot the following points and write the name of the figure obtained by joining them in order:
P(– 3, 2), Q(– 7, – 3), R(6, – 3), S(2, 2)
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उत्तर
Let X’ OX and Y’ OY be the coordinate axes and mark point on it. Here, point P(– 3, 2) lies in II quadrant, Q(– 7, – 3) lies in III quadrant, R(6, – 3) lies in IV quadrant and S(2, 2) lies in I quadrant. Plotting the points on the graph paper, the figure obtained is trapezium PQRS.
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संबंधित प्रश्न
Plot the following point on the graph paper:
(−5, −7)
Plot the following point on the graph paper:
(0, −4)
Write down the abscissa and ordinate of the following.
Q
Plot the following points in the coordinate plane. Join them in order. What type of geometrical shape is formed?
(0, 0) (−4, 0) (−4, −4) (0, −4)
Find the quadrants without plotting the point on a graph sheet.
(5, 7)
Plot the following points and check whether they are collinear or not:
(1, 1), (2, – 3), (– 1, – 2)
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
Plot the points P(1, 0), Q(4, 0) and S(1, 3). Find the coordinates of the point R such that PQRS is a square.
From the figure, answer the following:
- Write the points whose abscissa is 0.
- Write the points whose ordinate is 0.
- Write the points whose abscissa is –5.
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
