Advertisements
Advertisements
प्रश्न
Write two points of difference in the structures of diamond and graphite.
Advertisements
उत्तर
| Sl.No | Structure of Diamond | Structure of Graphite |
| 1. | Each carbon atom is joined to four other carbon atoms by strong covalent bonds to form a regular tetrahedron. | Each carbon atom is joined to three other carbon atoms by strong covalent bonds to form flat hexagonal rings. |
| 2. | Compact and rigid structure (hard) |
Layered structure (soft) |
APPEARS IN
संबंधित प्रश्न
An element L consists of molecules.
What type of bonding is present in the particles that make up L?
What type of bonds are present in hydrogen chloride and oxygen?
What is diamond? Of what substance is diamond made?
The solution of one of the following compounds will not conduct electricity. This compounds is:
(a) NaCl
(b) CCl4
(c) MgCl2
(d) CaCl2
One of the following is not an allotrope of carbon. This is:
(a) diamond
(b) graphite
(c) cumene
(d) buckministerfullerene
A saturated hydrocarbon has fifty hydrogen atom in its molecule. The number of carbon atoms in its molecule will be
(a) twenty five
(b) twenty four
(c) twenty six
(d) twenty seven
State the type of bonding in the following molecule.
Ammonium ion
Explain the following:
Polar covalent compounds are good conductors of electricity.
Name a neutral covalent molecule which contains one lone pair of electrons.
Compare the compounds carbon tetrachloride and sodium chloride with regard to solubility in water and electrical conductivity.
An element L consists of molecules.
What type of bonding is present in the particles that make up L?
Explain why carbon tetrachloride does not dissolve in water.
Explain the following:
Polar covalent compounds conduct electricity?
Covalent bonds can be single, double or triple covalent bonds. How many electrons are shared in each? Give an example of each type.
Define the functional group and complete the following table.
| S.I. No. | Functional Group | Compound | Formula |
| (1) | ______________ | _______________ |
C2H5OH |
| (2) | _______________ | _______________ | CH3CHO |
Which of the following are correct structural isomers of butane?
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}|\phantom{.....}|\\
\ce{H}\ce{H-C-H}\ce{H}\\
|\\
\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}\backslash\phantom{..}|\\
\phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
\phantom{.......}|\\
\phantom{.......}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\\
\end{array}\]
In covalent bond formation, the sharing of ______ electrons takes place in their outermost shell.
Statement (A): Covalent compounds are bad conductors of electricity.
Reason (B): Covalent compounds contain charged particles (ions)
Carbon can neither form C4- cation nor C4 anion. Why?
Explain dipole (polar) molecule by taking hydrogen chloride as an example.
