मराठी

Write the following function in the simplest form: tan-1 x/sqrt(a2-x2), |x| < a - Mathematics

Advertisements
Advertisements

प्रश्न

Write the following function in the simplest form:

`tan^(-1)  x/(sqrt(a^2 - x^2))`, |x| < a

बेरीज
Advertisements

उत्तर

Put x = a sin θ

⇒ `x/a` = sin θ

⇒ θ = `sin^(-1) (x/a)`

∴ `tan^(-1)  x/sqrt(a^2 - x^2) `

= `tan^(-1)  ((a sin θ)/(sqrt(a^2 - a^2 sin^2 θ)))`

= `tan^(-1)  ((asin θ)/(asqrt(1-sin^2 θ))) `

= `tan^(-1)  ((asin θ)/(acos θ))`

= `tan^(-1) (tan θ)`

= θ

= `sin^(-1)  x/a`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Inverse Trigonometric Functions - Exercise 2.2 [पृष्ठ ४८]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 2 Inverse Trigonometric Functions
Exercise 2.2 | Q 9 | पृष्ठ ४८

संबंधित प्रश्‍न

 

Prove that:

`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`

 

If `tan^-1(2x)+tan^-1(3x)=pi/4`, then find the value of ‘x’.


Prove `tan^(-1)  2/11 + tan^(-1)  7/24 = tan^(-1)  1/2`


Write the function in the simplest form:  `tan^(-1)  ((cos x - sin x)/(cos x + sin x)) `,` 0 < x < pi`


Find the value of the given expression.

`tan(sin^(-1)  3/5 + cot^(-1)  3/2)`


Prove that:

`sin^(-1)  8/17 + sin^(-1)  3/5 = tan^(-1)  77/36`


Prove that:

`cos^(-1)  12/13 + sin^(-1)  3/5 = sin^(-1)  56/65`


sin–1 (1 – x) – 2 sin–1 x = `pi/2`, then x is equal to ______.


Solve  `tan^(-1) -  tan^(-1)  (x - y)/(x+y)` is equal to

(A) `pi/2`

(B). `pi/3` 

(C) `pi/4` 

(D) `(-3pi)/4`


Solve the following equation for x:  `cos (tan^(-1) x) = sin (cot^(-1)  3/4)`


Prove that `3sin^(-1)x = sin^(-1) (3x - 4x^3)`, `x in [-1/2, 1/2]`


Find: ∫ sin x · log cos x dx


Find the value of the expression in terms of x, with the help of a reference triangle

cos (tan–1 (3x – 1))


Choose the correct alternative:

`tan^-1 (1/4) + tan^-1 (2/9)` is equal to


Choose the correct alternative:

sin–1(2 cos2x – 1) + cos1(1 – 2 sin2x) =


Choose the correct alternative:

If `sin^-1x + cot^-1 (1/2) = pi/2`, then x is equal to


Evaluate tan (tan–1(– 4)).


Show that `2tan^-1 {tan  alpha/2 * tan(pi/4 - beta/2)} = tan^-1  (sin alpha cos beta)/(cosalpha + sinbeta)`


If `tan^-1x = pi/10` for some x ∈ R, then the value of cot–1x is ______.


If α ≤ 2 sin–1x + cos–1x ≤ β, then ______.


Evaluate `cos[cos^-1 ((-sqrt(3))/2) + pi/6]`


The value of the expression `tan (1/2 cos^-1  2/sqrt(5))` is ______.


The value of cot–1(–x) for all x ∈ R in terms of cot–1x is ______.


The maximum value of sinx + cosx is ____________.


The value of `"tan"^ -1 (3/4) + "tan"^-1 (1/7)` is ____________.


`"sin" {2  "cos"^-1 ((-3)/5)}` is equal to ____________.


The value of expression 2 `"sec"^-1  2 + "sin"^-1 (1/2)`


`"cos" (2  "tan"^-1 1/7) - "sin" (4  "sin"^-1 1/3) =` ____________.


The value of `"tan"^-1 (1/2) + "tan"^-1(1/3) + "tan"^-1(7/8)` is ____________.


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


The value of `"cos"^-1 ("cos" ((33pi)/5))` is ____________.


`"sin"^-1 (1 - "x") - 2  "sin"^-1 "x" = pi/2`


`"sin"^-1 ((-1)/2)`


If `"sin" {"sin"^-1 (1/2) + "cos"^-1 "x"} = 1`, then the value of x is ____________.


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Domain and Range of tan-1 x = ________.


The value of `tan^-1 (x/y) - tan^-1  (x - y)/(x + y)` is equal to


If `cos^-1(2/(3x)) + cos^-1(3/(4x)) = π/2(x > 3/4)`, then x is equal to ______.


Write the following function in the simplest form:

`tan^-1 ((cos x - sin x)/(cos x + sin x)), (-pi)/4 < x < (3 pi)/4`


Solve for x: `sin^-1(x/2) + cos^-1x = π/6`


If \[\tan^{-1}\left(\frac{x}{2}\right)+\tan^{-1}\left(\frac{y}{2}\right)+\tan^{-1}\left(\frac{z}{2}\right)=\frac{\pi}{2}\]  then xy + yz + zx =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×