मराठी

Write the following function in the simplest form: tan^(–1) (sqrt((1 – cos x)/(1 + cos x))), 0 < x < π

Advertisements
Advertisements

प्रश्न

Write the following function in the simplest form:

`tan^(-1) (sqrt((1 - cos x)/(1 + cos x)))`, 0 < x < π

सोपे रूप द्या
Advertisements

उत्तर

`tan^(-1) (sqrt((1 - cosx)/(1 + cosx)))`

= `tan^(-1) (sqrt((2sin^2  x/2)/(2cos^2  x/2)))` 

= `tan^(-1) ((sin  x/2)/(cos  x/2)) `

= `tan^(-1) (tan  x/2)`

= `x/2`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Inverse Trigonometric Functions - EXERCISE 2.2 [पृष्ठ २९]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 2 Inverse Trigonometric Functions
EXERCISE 2.2 | Q 4. | पृष्ठ २९

संबंधित प्रश्‍न

Prove that `cot^(-1)((sqrt(1+sinx)+sqrt(1-sinx))/(sqrt(1+sinx)-sqrt(1-sinx)))=x/2;x in (0,pi/4) `


 

Prove that:

`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`

 

Prove the following: 

3cos1x = cos–1 (4x3 – 3x), `x ∈ [1/2, 1]`


Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`


if `tan^(-1)  (x-1)/(x - 2) + tan^(-1)  (x + 1)/(x + 2) = pi/4` then find the value of x.


Prove that `sin^(-1)  8/17 + sin^(-1)  3/5 = tan^(-1)  77/36`.


Prove that `cos^(-1)  4/5 + cos^(-1)  12/13 = cos^(-1)  33/65`.


sin (tan–1 x), |x| < 1 is equal to ______.


Solve  `tan^(-1) -  tan^(-1)  (x - y)/(x+y)` is equal to

(A) `pi/2`

(B). `pi/3` 

(C) `pi/4` 

(D) `(-3pi)/4`


If tan-1 x - cot-1 x = tan-1 `(1/sqrt(3)),`x> 0 then find the value of x and hence find the value of sec-1 `(2/x)`.


Solve for x : `tan^-1 ((2-"x")/(2+"x")) = (1)/(2)tan^-1  ("x")/(2), "x">0.`


Find the value of the expression in terms of x, with the help of a reference triangle

sin (cos–1(1 – x))


Find the value of the expression in terms of x, with the help of a reference triangle

`tan(sin^-1(x + 1/2))`


Prove that `tan^-1  2/11 + tan^-1  7/24 = tan^-1  1/2`


Prove that `tan^-1x + tan^-1y + tan^-1z = tan^-1[(x + y + z - xyz)/(1 - xy - yz - zx)]`


Prove that `tan^-1x + tan^-1  (2x)/(1 - x^2) = tan^-1  (3x - x^3)/(1 - 3x^2), |x| < 1/sqrt(3)`


Solve: `sin^-1  5/x + sin^-1  12/x = pi/2`


Choose the correct alternative:

If `cot^-1(sqrt(sin alpha)) + tan^-1(sqrt(sin alpha))` = u, then cos 2u is equal to


Choose the correct alternative:

If `sin^-1x + cot^-1 (1/2) = pi/2`, then x is equal to


Evaluate `tan^-1(sin((-pi)/2))`.


Evaluate tan (tan–1(– 4)).


Evaluate: `tan^-1 sqrt(3) - sec^-1(-2)`.


Show that `2tan^-1 {tan  alpha/2 * tan(pi/4 - beta/2)} = tan^-1  (sin alpha cos beta)/(cosalpha + sinbeta)`


If `sin^-1 ((2"a")/(1 + "a"^2)) + cos^-1 ((1 - "a"^2)/(1 + "a"^2)) = tan^-1 ((2x)/(1 - x^2))`. where a, x ∈ ] 0, 1, then the value of x is ______.


If |x| ≤ 1, then `2 tan^-1x + sin^-1 ((2x)/(1 + x^2))` is equal to ______.


If cos–1x > sin–1x, then ______.


The value of sin (2tan-1 (0.75)) is equal to ____________.


If sin `("sin"^-1 1/5 + "cos"^-1 "x") = 1,` then the value of x is ____________.


If `"tan"^-1 (("x" - 1)/("x" + 2)) + "tan"^-1 (("x" + 1)/("x" + 2)) = pi/4,` then x is equal to ____________.


The value of `"tan"^-1 (3/4) + "tan"^-1 (1/7)` is ____________.


`"tan" (pi/4 + 1/2 "cos"^-1 "x") + "tan" (pi/4 - 1/2 "cos"^-1 "x") =` ____________.


`"cos"^-1["cos"(2"cot"^-1(sqrt2 - 1))]` = ____________.


`"cos"^-1 1/2 + 2  "sin"^-1 1/2` is equal to ____________.


`"tan"^-1 (sqrt3)`


If `3  "sin"^-1 ((2"x")/(1 + "x"^2)) - 4  "cos"^-1 ((1 - "x"^2)/(1 + "x"^2)) + 2 "tan"^-1 ((2"x")/(1 - "x"^2)) = pi/3` then x is equal to ____________.


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Measure of ∠CAB = ________.


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Measure of ∠DAB = ________.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×