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प्रश्न
Solve: `sin^-1 5/x + sin^-1 12/x = pi/2`
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उत्तर
`sin^-1 5/x = pi/2 - sin^1 12/x`
`pi/2 - (cos^-1 5/x) = pi/2 - sin^-1 12/x`
`cos^-1 5/x = sin^-1 12/x`
cos θ = `5/x`
sin θ = `12/x`
`sin^2theta + cos^2theta` = 1
`(5/x)^2 + (12/x)^2` = 1
`25/x + 144/x^2` = 1
`169/x^2` = 1
x2 = 169
⇒ x = `+- 13`
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