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Write the General Term in the Expansion of (X2 – Yx)12, X ≠ 0 - Mathematics

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प्रश्न

Write the general term in the expansion of (x2 – yx)12x ≠ 0

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उत्तर

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पाठ 8: Binomial Theorem - Exercise 8.2 [पृष्ठ १७१]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 8 Binomial Theorem
Exercise 8.2 | Q 4 | पृष्ठ १७१

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The coefficients of the (r – 1)thrth and (r + 1)th terms in the expansion of (x + 1)n are in the ratio 1:3:5. Find n and r.


Find the middle terms in the expansion of:

(ii) \[\left( 2 x^2 - \frac{1}{x} \right)^7\]

 


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(ii)  \[\left( 1 - 2x + x^2 \right)^n\]


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(iii)  \[\left( 1 + 3x + 3 x^2 + x^3 \right)^{2n}\]

 


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(vii) \[\left( 3 - \frac{x^3}{6} \right)^7\]

  


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(viii)  \[\left( 2ax - \frac{b}{x^2} \right)^{12}\]

 


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(i) \[\left( \frac{3}{2} x^2 - \frac{1}{3x} \right)^9\]

 


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(iii)  \[\left( 2 x^2 - \frac{3}{x^3} \right)^{25}\]

 


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If the sum of odd numbered terms and the sum of even numbered terms in the expansion of  \[\left( x + a \right)^n\]  are A and B respectively, then the value of \[\left( x^2 - a^2 \right)^n\] is 

 

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