मराठी

Find the Middle Term in the Expansion Of: (Iii) ( X 2 − 2 X ) 10

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प्रश्न

Find the middle term in the expansion of: 

(iii) \[\left( x^2 - \frac{2}{x} \right)^{10}\]

 

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उत्तर

(iii) Here,
= 10    (Even number)
Therefore, the middle term is the \[\left( \frac{n}{2} + 1 \right)th\]   i.e. 6th term

\[Now, \]
\[ T_6 = T_{5 + 1} \]
\[ = ^{10}{}{C}_5 ( x^2 )^{10 - 5} \left( \frac{- 2}{x} \right)^5 \]
\[ = - \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2} \times 32 x^5 \]
\[ = - 8064  x^5 \]

 

 

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पाठ 18: Binomial Theorem - Exercise 18.2 [पृष्ठ ३८]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 18 Binomial Theorem
Exercise 18.2 | Q 13.3 | पृष्ठ ३८

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