मराठी

Without Expanding, Show that the Value of the Following Determinant is Zero: ∣ ∣ ∣ ∣ ∣ √ 23 + √ 3 √ 5 √ 5 √ 15 + √ 46 5 √ 10 3 + √ 115 √ 15 5 ∣ ∣ ∣ ∣ ∣

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प्रश्न

Without expanding, show that the value of the following determinant is zero:

\[\begin{vmatrix}\sqrt{23} + \sqrt{3} & \sqrt{5} & \sqrt{5} \\ \sqrt{15} + \sqrt{46} & 5 & \sqrt{10} \\ 3 + \sqrt{115} & \sqrt{15} & 5\end{vmatrix}\]

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उत्तर

\[\begin{vmatrix}\sqrt{23} + \sqrt{3} & \sqrt{5} & \sqrt{5} \\ \sqrt{15} + \sqrt{46} & 5 & \sqrt{10} \\ 3 + \sqrt{115} & \sqrt{15} & 5\end{vmatrix}\]
\[ = \begin{vmatrix}\sqrt{3} & \sqrt{5} & \sqrt{5} \\ \sqrt{15} & 5 & \sqrt{10} \\ 3 & \sqrt{15} & 5\end{vmatrix} + \begin{vmatrix}\sqrt{23} & \sqrt{5} & \sqrt{5} \\ \sqrt{46} & 5 & \sqrt{10} \\ \sqrt{115} & \sqrt{15} & 5\end{vmatrix}\]
\[ = \sqrt{3}\begin{vmatrix}1 & \sqrt{5} & \sqrt{5} \\ \sqrt{5} & 5 & \sqrt{10} \\ \sqrt{3} & \sqrt{15} & 5\end{vmatrix} + \sqrt{23}\begin{vmatrix}1 & \sqrt{5} & \sqrt{5} \\ \sqrt{2} & 5 & \sqrt{10} \\ \sqrt{5} & \sqrt{15} & 5\end{vmatrix}\]
\[ = \sqrt{3} \times \sqrt{5}\begin{vmatrix}1 & 1 & \sqrt{5} \\ \sqrt{5} & \sqrt{5} & \sqrt{10} \\ \sqrt{3} & \sqrt{3} & 5\end{vmatrix} + \sqrt{23} \times \sqrt{5}\begin{vmatrix}1 & \sqrt{5} & 1 \\ \sqrt{2} & 5 & \sqrt{2} \\ \sqrt{5} & \sqrt{15} & \sqrt{5}\end{vmatrix}\]
\[ = 0 + 0\]
\[ = 0\]

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पाठ 5: Determinants - Exercise 6.2 [पृष्ठ ५७]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 5 Determinants
Exercise 6.2 | Q 2.16 | पृष्ठ ५७

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