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प्रश्न
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उत्तर
Given, P = 1.5 kW= 1500 W, p.d. = 220 V
We know that,
P=VI
I = `"P"/"V" = 1500/220` = 6.8 A
Thus a fuse of rating 7A may be used with the appliance and it should be connected in the live wire before connectimg it to the appliance.
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संबंधित प्रश्न
The lamps in a house hold circuit are connected in parallel because:
(a) this way they required less current
(b) if one lamp fails the others remain lit
(c) this way they require less power
(d) if one lamp fails the other also fail
Find the effective resistance in the following circuit diagrams (Fig.):
A wire is passed through a piece of cardboard as shown in fig .. An electric current flows vertically down the wire and then flows back up. The two sections of the write are observed to repel each other.
(a) Wi th the aid of a diagram, describe how you would plot the magnetic field lines on the card .
(b) Sketch the magnetic field patterns around both the sections of the wire. Use your sketch to explain why the two sections repel each other.
(c) The repulsive force between the two sections is small. What changes could be made to increase it?
An electric bulb is rated 250 W, 230 V.
- the energy consumed in one hour, and
- the time in which the bulb will consume 1.0 kWh energy when connected to 230 V mains.
True or False – If False give the correct answer
The representation of the electric current is A
Problems for practice:
If 5A current flows through a circuit, then convert the current in terms of microampere?
