Question

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly

पर्याय

• 10²⁰

• 10¹⁶

• 10¹⁸

• 10²³

Answer 1

10²⁰

Explanation - 

Current, i = 1A

Time, t = 16s

`"i" = "q"/"t"`

`"q" = "i" xx "t"`

q = 1 × 16

q = 16 C

Now, 

q = n × e

where, n is number of electrons lost or gained
e = charge on 1 electron (1.6 × 10^-19 C)

`"n" = "q"/"e"`

`n = 16/(1.6 xx 10^(-19))`

n = 10²⁰