Advertisements
Advertisements
प्रश्न
Two resistors of 4 Ω and 6 Ω are connected in parallel. The combination is
connected across a 6 volt battery of negligible resistance. Calculate:
( i) The power supplied by the battery,
(ii) The power dissipated in each resistor.
Advertisements
उत्तर
Total resistance of resitors of 4 Ω and 6 Ω in parallel is:
RP = `[1/4 + 1/6]^-1 = 2.4 Omega`
Given voltage supply= 6 volt
(i) Power supplied by the battery, P = `"V"^2/"R" = (6 xx 6)/2.4` = 15 watt
(ii) Power dissipated in 4 Ω resistor, P1 = `"V"^2/"R" = (6 xx 6)/4` = 9 watt
Power dissipated in 6 Ω resistor, P1 `"V"^2/"R" = (6 xx 6)/6` = 6 watt
APPEARS IN
संबंधित प्रश्न
The SI unit of charge is volt.
In the circuit shown below, the voltmeter reads 10 V.
(a) What is the combined resistance?
(b) What current flows?
(c) What is the p.d. across 2 Ω resistor?
(d) What is the p.d. across 3 Ω resistor?
Ten bulbs are connected in a series circuit to a power supply line. Ten identical bulbs are connected in a parallel circuit to an identical power supply line.
(b) In which circuit, if one bulbs be brighter?
Find the potential difference required to pass a current of 0.2 A in a wire of resistance 20Ω
Find the effective resistance in the following circuit diagrams (Fig.):
Calculate the current through a 60 W lamp rated 250 V. If the line voltage falls to 200 V, how is power consumed by the bulb affected?
Explain, why the potential difference across the terminals of a cell is more when the cell is not in use than it is when the cell is being used.
The number of electrons constituting a 1-coulomb charge is ______.
