मराठी

Two Charges of Magnitudes +4q and − Q Are Located at Points (A, 0) and (− 3a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘2a’ with Its Centre

Advertisements
Advertisements

प्रश्न

Two charges of magnitudes +4Q and − Q are located at points (a, 0) and (− 3a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘2a’ with its centre at the origin?

Advertisements

उत्तर

Gauss’ theorem states that the electric flux through a closed surface enclosing a charge is equal to `1/epsi_0`times the magnitude of the charge enclosed.

The sphere enclose charge = +4Q.

Thus,`phi = (4Q)/epsi_0`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2012-2013 (March) All India Set 3

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Consider a uniform electric field E = 3 × 103 `hat i` N/C.

  1. What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?
  2. What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?

Given a uniform electric filed \[\vec{E} = 4 \times {10}^3 \ \hat{i} N/C\]. Find the flux of this field through a square of 5 cm on a side whose plane is parallel to the Y-Z plane. What would be the flux through the same square if the plane makes a 30° angle with the x-axis?

 

Figure shows three point charges +2q, −q and + 3q. Two charges + 2q and −q are enclosed within a surface ‘S’. What is the electric flux due to this configuration through the surface ‘S’?


Mark the correct options:


If the flux of the electric field through a closed surface is zero,

(a) the electric field must be zero everywhere on the surface
(b) the electric field may be zero everywhere on the surface
(c) the charge inside the surface must be zero
(d) the charge in the vicinity of the surface must be zero


The electric field in a region is given by `vec"E"` = 5 `hatk`N/C. Calculate the electric flux Through a square of side 10.0 cm in the following cases

  1. The square is along the XY plane
  2. The square is along XZ plane
  3. The normal to the square makes an angle of 45° with the Z axis.

If the flux of the electric field through a closed surface is zero, then ______.

The electric field intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance rir r(r > R) from its axis is ______.


The electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 20 V-m. The flux over a concentric sphere of radius 20 cm will be ______.


An electric field is given by `(6 hat i + 5 hat j + 3 hat k)` N/C. The electric flux through a surface area `30 hat i` m2 lying in YZ-plane (in SI unit) is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×