Advertisements
Advertisements
प्रश्न
Two charges of magnitudes +4Q and − Q are located at points (a, 0) and (− 3a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘2a’ with its centre at the origin?
Advertisements
उत्तर
Gauss’ theorem states that the electric flux through a closed surface enclosing a charge is equal to `1/epsi_0`times the magnitude of the charge enclosed.
The sphere enclose charge = +4Q.
Thus,`phi = (4Q)/epsi_0`
APPEARS IN
संबंधित प्रश्न
How does the electric flux due to a point charge enclosed by a spherical Gaussian surface get affected when its radius is increased?
Write S.I unit of electric flux.
Given the electric field in the region `vecE=2xhati`, find the net electric flux through the cube and the charge enclosed by it.
Consider a uniform electric field E = 3 × 103 `hat i` N/C.
- What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?
- What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?
Two charges of magnitudes −2Q and +Q are located at points (a, 0) and (4a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘3a’ with its centre at the origin?
The S.I. unit of electric flux is ______
The electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 20 V-m. The flux over a concentric sphere of radius 20 cm will be ______.
A hollow sphere of radius R has a point charge q at its centre. Electric flux emanating from the sphere is X. How will the electric flux change, if at all, when charge q is replaced by an electric dipole?
A hollow cylinder has a charge of 'q' C within it. If 𝜙 is the electric flux associated with the curved surface B, the flux linked with the plane surface A will be ______.
