Advertisements
Advertisements
प्रश्न
Three forces A, B and C are acting on a rigid body which can turn about O in fig.9. If all the three forces are applied simultaneously, in which direction will the body move? Explain.

Advertisements
उत्तर
The body will move in the direction of net torque
Net torque = sum of clockwise moments - sum of anticlockwise moments
In the given figure, force 40N is acting clockwise and forces 20N and 60N are acting anticlockwise
Net torque = (40 x 3) - [(20 x 2) + (60 x 1)}
= 120 - 100
= 20 Nm
Hence the body will move in clockwise direction about 'O'
APPEARS IN
संबंधित प्रश्न
In Fig. a force F is applied in a direction passing through the pivoted point O of the body. Will the body rotate? Give reason to support your answer.

A tall building has wide foundations.
Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force.
The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.
What do you understand by the clockwise and anticlockwise moment of force? When is it taken positive?
The figure shows two forces each of magnitude 10 N acting at the point A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of two forces about the point.
- A,
- B and
- O situated exactly at the middle of the two forces.

Classify the following amongst contact and non-contact forces.
normal reaction force,
Write the expression for the moment of force about a given axis.
Give any two effects of a force on a non-rigid body.
Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
