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प्रश्न
Fig. shows a uniform meter scale weighing 100 N pivoted at its centre. Two weights of 500 N and 300 N are hung from the ruler as shown in fig.

(i) Calculate total clockwise and anticlockwise moments.
(ii) Calculate difference in clockwise moment and anticlockwise moment.
(iii) Calculate the distance from O where a 100 N weight should be suspended to balance the meter scale.
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उत्तर
Let the weight 500 N be hung from the 40cm mark and the weight 300N be hung from the 80 cm mark
(i) Then, total clockwise moment = 500 x (50 - 40) = 500 x 10 = 5000 Nm
Total anticlockwise moment = 300 x (80 - 50) = 300 x 30 = 9000 Nm
(ii) Difference in clockwise and anticlockwise moment = 9000 - 5000 = 4000Nm
(iii) Let the 100 N weight be hung at a distance 'd' from the point 'o' to its left
Then,total clockwise moment = 5000 + 100 d
In balanced condition, sum of clockwise moments = sum of anticlockwise moments
5000 + 100 d = 9000
or 100 d = 4000
or d = 40cm
the weight 100 N should be a hung from the 40cm mark so as to balance the scale.
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