मराठी

Fig. 10 Shows a Uniform Meter Scale Weighing 100 N Pivoted at Its Centre. Two Weights of 500 N and 300 N Are Hung from the Ruler as Shown in Fig. 10.

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प्रश्न

Fig.  shows a uniform meter scale weighing 100 N pivoted at its centre. Two weights of 500 N and 300 N are hung from the ruler as shown in fig.

(i)    Calculate total clockwise and anticlockwise moments.
(ii)    Calculate difference in clockwise moment and anticlockwise moment.
(iii)    Calculate the distance from O where a 100 N weight should be suspended to balance the meter scale.

आकृती
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उत्तर

Let the weight 500 N be hung from the 40cm mark and the weight 300N be hung from the 80 cm mark

(i) Then, total clockwise moment = 500 x (50 - 40) = 500 x 10 = 5000 Nm

Total anticlockwise moment = 300 x (80 - 50) = 300 x 30 = 9000 Nm

(ii) Difference in clockwise and anticlockwise moment = 9000 - 5000  = 4000Nm

(iii) Let the 100 N weight be hung at a distance 'd' from the point 'o' to its left

Then,total clockwise moment = 5000 + 100 d

In balanced condition, sum of clockwise moments = sum of anticlockwise moments 

5000 + 100 d = 9000

or 100 d = 4000

or d = 40cm

the weight 100 N should be a hung from the 40cm mark so as to balance the scale.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Force, Work, Energy and Power - Exercise 3 [पृष्ठ ५८]

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फ्रँक Physics Part 2 [English] Class 10 ICSE
पाठ 1 Force, Work, Energy and Power
Exercise 3 | Q 8 | पृष्ठ ५८

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