Advertisements
Advertisements
प्रश्न
The perimeter of a square is 60 m, find:
(i) its each side its area
(ii) its new area obtained on increasing
(iii) each of its sides by 2 m.
Advertisements
उत्तर
Perimeter of a square = 60 m
(i) Perimeter of a square = 4 x side
60 m = 4 x side
`60/4` = side 4
∴side = 15 m
(ii) Area of square = (side)² = (15 m)²
= 15 m x 15 m
= 225 m²
(iii) Increased each side = 2 m
Side of square = 15 m
New length of side = (2m + 15m)
= 17m
∴ New Area of square = (17m)² = 17m x 17m = 289 m2
APPEARS IN
संबंधित प्रश्न
In each of the following cases, ABCD is a square and PQRS is a rectangle. Find, in each case, the area of the shaded portion.
(All measurements are in metre).
(i)

(ii)

A rectangle with length = 18 cm and breadth = 12 cm has same perimeter as that of a regular pentagon. Find the side of the pentagon.
Each side of a square is 45 cm and a rectangle has length 50 cm. If the perimeters of both (square and rectangle) are same, find the breadth of the rectangle.
Find the perimeter of a rectangle whose area = 2600 m² and breadth = 50 m.
If the length of a rectangle is 14 m and its breadth is 10 m, what is its perimeter?

Each rectangle is made out of 12 equal squares, so all have the same area, but the length of the boundary will be different.
Which of these rectangles has the smallest perimeter?
A rectangular path of 60 m length and 3 m width is covered by square tiles of side 25 cm. How many tiles will there be in one row along its width? How many such rows will be there? Find the number of tiles used to make this path?
The area of a rectangular field is 1600 sq m. If the length of the field is 80 m, find the perimeter of the field.
A rectangular piece of land measures 0.7 km by 0.5 km. Each side is to be fenced with 4 rows of wires. What is the length of the wire needed?
Find the cost of fencing a rectangular park of length 175 m and breadth of 125 m at the rate of ₹ 12 per metre.
