Advertisements
Advertisements
प्रश्न
The normal pressure of air is 76 cm of mercury. Calculate the pressure in SI units.
[Density of mercury = 13600 kg/m3 and g = 10 m/s2]
Advertisements
उत्तर
Height of mercury column = h = 76 cm
h = 0.76 m
Density of mercury =ρ = 13600 kg/m3
Acceleration due to gravity = g = 10 m/s2
Pressure = P = ?
P = hρg
P = 0.76 × 13600 × 10 = 103360 N/m2
APPEARS IN
संबंधित प्रश्न
Calculate the pressure exerted by 0.8 m vertical length of alcohol of density 0.80 gcnr5 in SI units.
[Take g = 10 ms−2].
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
The pressure of water on the ground floor is 160000 Pa. Calculate the pressure on the fifth floor, at a height of 15 m.
What fact about liquid pressure does the following diagram in the following figure illustrate?
What is the SI unit of density?
