Advertisements
Advertisements
प्रश्न
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
Advertisements
उत्तर
Density of mercury = ρHg = 13600 kgm−3
Density of seawater = ρwater = 1040 kgm−3
Height of seawater column = hwater = 960 m
Height of mercury column = hHg =?
According to the question,
Pressure due to mercury column = Pressure due to seawater column
ρHg × hHg × g = ρwater × hwater
hHg = `(ρ_("water")xx"h"_"water")/ρ_"Hg"`
= `(1040xx960)/13600`
= 73.41 m
APPEARS IN
संबंधित प्रश्न
Pressure at the bottom of the sea at some particular place is 8968960 Pa. If the density of seawater is 1040 kgm3 calculate the depth of the sea. Take g = 9.8 ms−2. Neglect the pressure of the atmosphere.
The pressure of water on the ground floor, in a water pipe is 150000 Pa, whereas pressure on the fourth floor is 30000 Pa. Calculate the height of the fourth floor. Take g = 10 ms−2.
The pressure of water on the ground floor is 160000 Pa. Calculate the pressure on the fifth floor, at a height of 15 m.
(i) Calculate the height of a water column which will exert on its base the same
Pressure as the 70 cm column of mercury.
(ii) Will the height of the water column change if the cross-section of the water column is made wider?
