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प्रश्न
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
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उत्तर
Density of mercury = ρHg = 13600 kgm−3
Density of seawater = ρwater = 1040 kgm−3
Height of seawater column = hwater = 960 m
Height of mercury column = hHg =?
According to the question,
Pressure due to mercury column = Pressure due to seawater column
ρHg × hHg × g = ρwater × hwater
hHg = `(ρ_("water")xx"h"_"water")/ρ_"Hg"`
= `(1040xx960)/13600`
= 73.41 m
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