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The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on surface of planet X

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प्रश्न

The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on the surface of planet X such that the acceleration of the planet X is n times greater than the Earth is

पर्याय

  • 0.9 n

  • `0.9/"n""m"`

  • 0.9 n2m

  • `0.9/"n"^2`

MCQ
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उत्तर

0.9 n

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Oscillations - Evaluation [पृष्ठ २१८]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Oscillations
Evaluation | Q I. 3. | पृष्ठ २१८

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