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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume. Calculate the rate of the reaction when total pressure is 0.65 atm. - Chemistry

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प्रश्न

The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume.

\[\ce{SO2Cl2_{(g)} -> SO2_{(g)} + Cl2_{(g)}}\]

Experiment Time/s–1 Total pressure/atm
1 0 0.5
2 100 0.6

Calculate the rate of the reaction when total pressure is 0.65 atm.

संख्यात्मक
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उत्तर १

The thermal decomposition of SO2Cl2 at a constant volume is represented by the following equation.

\[\ce{SO2Cl2_{(g)} -> SO2_{(g)} + Cl2_{(g)}}\]

At t = 0 P0 0 0
At t = t P0 − p p p

After time t, total pressure, Pt = (P0 − p) + p + p

⇒ Pt = (P0 + p)

⇒ p = Pt − P0

∴ P0 − p = P− (Pt − P0)

= 2 P0 − Pt

For a first order reaction,

k = `2.303/t log  P_0/(P_0 - p)`

When t = 100 s, k = `2.303/(100 s)log  0.5/(2 xx 0.5 - 0.6)`

When Pt = 0.65 atm,

P0 + p = 0.65

⇒ p = 0.65 − P0

= 0.65 − 0.5

= 0.15 atm

∴ When the total pressure is 0.65 atm, pressure of SOCl2 is \[\ce{P_{SO_2Cl_2}}\] = P0 − p

= 0.5 − 0.15

= 0.35 atm

∴ The rate of equation, when total pressure is 0.65 atm, is given by,

Rate = \[\ce{k(P_{SO_2Cl_2})}\]

= (2.23 × 10−3 s−1) × (0.35 atm)

= 7.8 × 10−4 atm s−1

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उत्तर २

If P0 is the initial pressure and Pt at time t, we have

k = `2.303/t log_10  P_0/(2P_0 - P_t)`

Given, P0 = 0.5 atm, Pt (at t = 100 s) = 0.6 atm

k = `2.303/t log_10  P_0/(2P_0 - P_t)`

= `2.303/100 log_10  0.5/(2 xx 0.5 - 0.6)`

= 2.2318 × 10−3 s−1

When, Pt = 0.65 atm, i.e., P0 + x = 0.65

∴ x = 0.65 − P0

= 0.65 − 0.5

x = 0.15 atm

Pressure of SO2Cl2 when the total pressure is 0.65 atm, i.e.,

`P_(SO_2Cl_2)` = P0 − x

= 0.50 − 0.15

= 0.35 atm

∴ The required rate of reaction = k × `P_(SO_2Cl_2)`

= 2.2318 × 10−3 × 0.35

= 7.81 × 10−4 atm s−1

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पाठ 3: Chemical Kinetics - Exercises [पृष्ठ ८७]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 3 Chemical Kinetics
Exercises | Q 3.21 | पृष्ठ ८७

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