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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

The difference between the two molar specific heats of gas is 9000 J/kg K. If the ratio of the two specific heats is 1.5, calculate the two molar specific heats. - Physics

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प्रश्न

The difference between the two molar specific heats of gas is 9000 J/kg K. If the ratio of the two specific heats is 1.5, calculate the two molar specific heats.

संख्यात्मक
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उत्तर

Given,

Cp - Cv = 9000 J/kg K

`"C"_"p"/"C"_"v" = 1.5`

Cv = ?

Cp = ?

`"C"_"p"/"C"_"v" = 1.5`

`"C"_"p" = 1.5 " C"_"v"`

`"C"_"p" - "C"_"v" = 9000`

`1.5 " C"_"v" - "C"_"v" = 9000`

`0.5 " C"_"v" = 9000`

`therefore "C"_"v" = 9000/0.5`

= 18000 J/kg k

`therefore "C"_"p" = 9000 + "C"_"v"`

= 9000 + 18000

= 27000 J/kg k

∴ Two molar specific heats ore 18000 J/kg k and 27000 J/kg k.

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