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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Solve the following problem. A particle moves in a circle with constant speed of 15 m/s. The radius of the circle is 2 m. Determine the centripetal acceleration of the particle.

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प्रश्न

Solve the following problem.

A particle moves in a circle with a constant speed of 15 m/s. The radius of the circle is 2 m. Determine the centripetal acceleration of the particle.

बेरीज
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उत्तर

Given: v = 15 m/s, r = 2m

To find: Centripetal acceleration (a)

Formulae: a = `"v"^2/"r"`

Calculation: From formula,

a = `(15)^2/2 = 225/2`

∴ a = 112.5 m/s2

The centripetal acceleration of the particle is 112.5 m/s2.

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पाठ 3: Motion in a Plane - Exercises [पृष्ठ ४६]

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बालभारती Physics [English] Standard 11 Maharashtra State Board
पाठ 3 Motion in a Plane
Exercises | Q 3. (x) | पृष्ठ ४६

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