मराठी

Show that the signum function f : R → R, given by , f(x) = {(1, if x > 0), (0, if x  = 0), (–1, if x < 0):} is neither one-one nor onto.

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प्रश्न

Show that the signum function f : R → R, given by

`f(x) = {(1", if"  x > 0), (0", if"  x  = 0), (-1", if"  x < 0):}`

is neither one-one nor onto.

बेरीज
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उत्तर

f : R → R, given by `f(x) = {(1", if"  x > 0), (0", if"  x  = 0), (-1", if"  x < 0):}`

It is seen that f(1) = f(2) = 1, but 1 ≠ 2.

∴ f is not one-one.

Now, as f(x) takes only 3 values (1, 0, or –1) for the element –2 in co-domain R, there does not exist any x in domain R such that f(x) = –2.

∴ f is not onto.

Hence, the signum function is neither one-one nor onto.

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पाठ 1: Relations and Functions - EXERCISE 1.2 [पृष्ठ ११]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 1 Relations and Functions
EXERCISE 1.2 | Q 5. | पृष्ठ ११

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