मराठी

Show that the function f(x) = 4x3 – 18x2 + 27x – 7 has neither maxima nor minima.

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प्रश्न

Show that the function f(x) = 4x3 – 18x2 + 27x – 7 has neither maxima nor minima.

बेरीज
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उत्तर

f(x) = 4x3 – 18x2 + 27x – 7

f′(x) = 12x2 – 36x + 27

= 3(4x2 – 12x + 9)

= 3(2x – 3)2

f'(x) = 0

⇒ x = `3/2` .....(critical point)

Since f′(x) > 0 for all x < `3/2` and for all x > `3/2`

Hence x = `3/2` is a point of inflexion

i.e., neither a point of maxima nor a point of minima.

x = `3/2` is the only critical point, and f has neither maxima nor minima.

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पाठ 6: Application Of Derivatives - Solved Examples [पृष्ठ १२२]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 6 Application Of Derivatives
Solved Examples | Q 6 | पृष्ठ १२२

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