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Determine the maximum and minimum value of the following function. f(x) = x2+16x - Mathematics and Statistics

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प्रश्न

Determine the maximum and minimum value of the following function.

f(x) = `x^2 + 16/x`

बेरीज
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उत्तर

f(x) = `x^2 + 16/x`

∴ f'(x) = `2x - 16/x^2`

and f"(x) = `2 + 32/x^3`

Consider, f'(x) = 0

∴ `2x - 16/x^2` = 0

∴ 2x = `16/x^2`

∴ x3 = 8

∴ x = 2

The maximum value is 2.

f(x) = `x^2 + 16/x`

For x = 2

f''(2) = `2 + 32/2^3`

= `2 + 32/8`

= 2 + 4

= 6 > 0

∴ f(x) attains minimum value at x = 2

∴ Minimum value = f(2) = `(2)^2 + 16/2 = 4 + 8` = 12

∴ The function f(x) has minimum value 12 at x = 2.

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पाठ 4: Applications of Derivatives - Exercise 4.3 [पृष्ठ १०९]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 4 Applications of Derivatives
Exercise 4.3 | Q 1.3 | पृष्ठ १०९

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