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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Divide the number 20 into two parts such that their product is maximum.

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प्रश्न

Divide the number 20 into two parts such that their product is maximum.

बेरीज
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उत्तर

The given number is 20.

Let x be one part of the number and y be the other part.

∴ x + y = 20

∴ y = (20 - x)      ...(i)

The product of two numbers is xy.

∴ f(x) = xy = x(20 - x) = 20x - x2

∴ f'(x) = 20 - 2x  and  f''(x) = - 2

Consider, f '(x) = 0

∴ 20 - 2x = 0

∴ 20 = 2x

∴ x = 10

For x = 10,

f ''(10) = - 2 < 0

∴ f(x), i.e., product is maximum at x = 10

and 10 + y = 20      ....[from (i)]

i.e., y = 10.

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पाठ 4: Applications of Derivatives - Exercise 4.3 [पृष्ठ १०९]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 4 Applications of Derivatives
Exercise 4.3 | Q 2 | पृष्ठ १०९

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