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Show that following function have continuous extension to the point where f(x) is not defined. Also find the extension : f(x) = 3sin2x+2cosx(1-cos2x)2(1-cos2x), for x ≠ 0 - Mathematics and Statistics

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प्रश्न

Show that following function have continuous extension to the point where f(x) is not defined. Also find the extension :

f(x) = `(3sin^2 x + 2cos x(1 - cos 2x))/(2(1 - cos^2x)`, for x ≠ 0

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उत्तर

f(x) = `(3sin^2 x + 2cos x(1 - cos 2x))/(2(1 - cos^2x)`, for x ≠ 0

∴ f(0) is not defined

`lim_(x -> 0) "f"(x) =  lim_(x -> 0) (3sin^2x + 2cosx(1 - cos2x))/(2(1 - cos^x))`

= `lim_(x -> 0) (3sin^2x + 2cosx (2sin^2x))/(2sin^2x)`

= `lim_(x -> 0) (sin^2x (3 + 4cosx))/(2sin^2x)`

= `lim_(x -> 0) (3 + 4cosx)/2   ...[(because x -> 0","  x ≠ 0),(therefore  sinx ≠ sin 0 = 0),(therefore sin^2x ≠ 0)]`

= `1/2 lim_(x -> 0) (3 + 4 cos x)`

= `1/2 (3 + 4 cos 0)`

= `7/2`

If we define f(0) = `7/2`, f will be continuous at x = 0

∴ continuous extension = `7/2` i.e. f(0) = `7/2`.

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पाठ 8: Continuity - EXERCISE 8.1 [पृष्ठ १७३]

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