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∫ Sec 2 X √ 4 + Tan 2 X D X - Mathematics

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प्रश्न

\[\int\frac{\sec^2 x}{\sqrt{4 + \tan^2 x}} dx\]
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उत्तर

 

` ∫   { sec^2 x  dx}/{\sqrt{4 + tan^2 x}} `


\`text{ let } tan  x }= t `
\[ \Rightarrow \sec^2 x dx = dt\]
Now, ` ∫   { sec^2 x  dx}/{\sqrt{4 + tan^2 x}} `
\[ = \int\frac{dt}{\sqrt{2^2 + t^2}}\]
\[ = \text{ log } \left| t + \sqrt{4 + t^2} \right| + C\]
\[ = \text{ log }\left| \text{ tan x }+ \sqrt{4 + \tan^2 x} \right| + C\]

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पाठ 19: Indefinite Integrals - Exercise 19.18 [पृष्ठ ९८]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.18 | Q 2 | पृष्ठ ९८

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