मराठी

Prove the Following Trigonometric Identities. (Tan a + Tan B)/(Cot a + Cot B) = Tan a Tan B - Mathematics

Advertisements
Advertisements

प्रश्न

Prove the following trigonometric identities.

`(tan A + tan B)/(cot A + cot B) = tan A tan B`

Advertisements

उत्तर

 We have to prove `(tan A + tan B)/(cot A + cot B) = tan A tan B`

Now

`(tan A + tan B)/(cot A + cot B) = (tan A + tan B)/(1/tan A + 1/tanB)`

`= (tan A + tan B)/((tan B + tan A)/(tan A tan B))`

= tan A tan B

Hence proved.

 

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Trigonometric Identities - Exercise 11.1 [पृष्ठ ४६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 11 Trigonometric Identities
Exercise 11.1 | Q 71 | पृष्ठ ४६

संबंधित प्रश्‍न

Prove the following identities:

`(i) (sinθ + cosecθ)^2 + (cosθ + secθ)^2 = 7 + tan^2 θ + cot^2 θ`

`(ii) (sinθ + secθ)^2 + (cosθ + cosecθ)^2 = (1 + secθ cosecθ)^2`

`(iii) sec^4 θ– sec^2 θ = tan^4 θ + tan^2 θ`


Show that `sqrt((1+cosA)/(1-cosA)) = cosec A + cot A`


Prove that (cosec A – sin A)(sec A – cos A) sec2 A = tan A.


If sin θ + cos θ = x, prove that  `sin^6 theta + cos^6 theta = (4- 3(x^2 - 1)^2)/4`


Prove the following identities:

(sin A + cosec A)2 + (cos A + sec A)2 = 7 + tan2 A + cot2 A


Prove the following identities:

`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`


` (sin theta - cos theta) / ( sin theta + cos theta ) + ( sin theta + cos theta ) / ( sin theta - cos theta ) = 2/ ((2 sin^2 theta -1))`


If x= a sec `theta + b tan theta and y = a tan theta + b sec theta ,"prove that" (x^2 - y^2 )=(a^2 -b^2)`


Write the value of ` sin^2 theta cos^2 theta (1+ tan^2 theta ) (1+ cot^2 theta).`


Write the value of `4 tan^2 theta  - 4/ cos^2 theta`


If  `sin theta = 1/2 , " write the value of" ( 3 cot^2 theta + 3).`


Find the value of sin ` 48° sec 42° + cos 48°  cosec 42°`

 


Find the value of `(cos 38° cosec 52°)/(tan 18° tan 35° tan 60° tan 72° tan 55°)`


If x = a sec θ cos ϕ, y = b sec θ sin ϕ and z = c tan θ, then\[\frac{x^2}{a^2} + \frac{y^2}{b^2}\]


If sec θ = `25/7`, then find the value of tan θ.


Prove that `(sin (90° - θ))/cos θ + (tan (90° - θ))/cot θ + (cosec (90° - θ))/sec θ = 3`.


If x = a tan θ and y = b sec θ then


Choose the correct alternative:

`(1 + cot^2"A")/(1 + tan^2"A")` = ?


`(1 - tan^2 45^circ)/(1 + tan^2 45^circ)` = ?


If tan α + cot α = 2, then tan20α + cot20α = ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×