Advertisements
Advertisements
प्रश्न
Prove the following identity :
`(1 - cos^2θ)sec^2θ = tan^2θ`
Advertisements
उत्तर
`(1 - cos^2θ)sec^2θ = tan^2θ`
Consider L.H.S = `sin^2θ1/cos^2θ`
= `tan^2θ` = RHS
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identity:
`sqrt((1 + sin A)/(1 - sin A)) = sec A + tan A`
Prove the following trigonometric identities. `(1 - cos A)/(1 + cos A) = (cot A - cosec A)^2`
`If sin theta = cos( theta - 45° ),where theta " is acute, find the value of "theta` .
If `sec theta + tan theta = x," find the value of " sec theta`
\[\frac{x^2 - 1}{2x}\] is equal to
Prove the following identity :
`(1 + sinθ)/(cosecθ - cotθ) - (1 - sinθ)/(cosecθ + cotθ) = 2(1 + cotθ)`
Prove that (sin θ + cosec θ)2 + (cos θ + sec θ)2 = 7 + tan2 θ + cot2 θ.
If tan α = n tan β, sin α = m sin β, prove that cos2 α = `(m^2 - 1)/(n^2 - 1)`.
Prove that `(sin θ)/(sec θ + 1) + (sin θ)/(sec θ - 1) = 2 cot θ`.
Prove that `(1 + sec A)/(sec A) = (sin^2A)/(1 - cos A)`.
