मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Prove that (cos(90^circ – A))/(sin A) = (sin(90^circ – A))/(cos A).

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प्रश्न

Prove that `(cos(90^circ - A))/(sin A) = (sin(90^circ - A))/(cos A)`.

सिद्धांत
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उत्तर

L.H.S. = `(cos(90^circ - A))/(sin A)`

= `(sin A)/(sin A)`

= 1

R.H.S. = `(sin(90^circ - A))/(cos A)`

= `(cos A)/(cos A)`

= 1

∴ L.H.S. = R.H.S.

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पाठ 6: Trigonometry - Exercise

संबंधित प्रश्‍न

(secA + tanA) (1 − sinA) = ______.


Prove the following trigonometric identities

`cos theta/(1 - sin theta) = (1 + sin theta)/cos theta`


`Prove the following trigonometric identities.

`(sec A - tan A)^2 = (1 - sin A)/(1 +  sin A)`


Prove the following identities:

`1/(1 + cosA) + 1/(1 - cosA) = 2cosec^2A`


Prove the following identities:

`1/(sinA + cosA) + 1/(sinA - cosA) = (2sinA)/(1 - 2cos^2A)`


Prove that:

`(tanA + 1/cosA)^2 + (tanA - 1/cosA)^2 = 2((1 + sin^2A)/(1 - sin^2A))`


Show that : `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec A cosec A`


Prove the following identities:

sec4 A (1 – sin4 A) – 2 tan2 A = 1


Write the value of `(1 + cot^2 theta ) sin^2 theta`. 


If `tan theta = 1/sqrt(5), "write the value of" (( cosec^2 theta - sec^2 theta))/(( cosec^2 theta - sec^2 theta))`.


Prove the following identity :

`sec^2A.cosec^2A = tan^2A + cot^2A + 2`


Prove the following identities:

`(tan"A"+tan"B")/(cot"A"+cot"B")=tan"A"tan"B"`


Evaluate:

`(tan 65^circ)/(cot 25^circ)`


Prove the following identities: sec2 θ + cosec2 θ = sec2 θ cosec2 θ.


Prove that: `1/(cosec"A" - cot"A") - 1/sin"A" = 1/sin"A" - 1/(cosec"A" + cot"A")`


Prove the following identities.

cot θ + tan θ = sec θ cosec θ


Prove that `(sin θ + tan θ)/(cos θ) = tan θ (1 + sec θ)`.


Prove that cot2θ – tan2θ = cosec2θ – sec2θ.


If 1 + sin2θ = 3 sin θ cos θ, then prove that tan θ = 1 or `1/2`.


Show that, cotθ + tanθ = cosecθ × secθ

Solution :

L.H.S. = cotθ + tanθ

= `cosθ/sinθ + sinθ/cosθ`

= `(square + square)/(sinθ xx cosθ)`

= `1/(sinθ xx cosθ)` ............... `square`

= `1/sinθ xx 1/square`

= cosecθ × secθ

L.H.S. = R.H.S

∴ cotθ + tanθ = cosecθ × secθ


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